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NEW QUESTION: 1
You have a table named ORDERS that contains 10,514,003 Orders. The ORDERS table has an IDENTITY(1,1) column named ORDER_ID. ORDER_ID is the UNIQUE CLUSTERED INDEX and PRIMARY KEY for the table. The first ORDER_ID is 1. There are no missing ORDER_IDs in the set.
Based on table usage patterns, you decide to use partitioning on this table based off of the ORDER_ID column.
You need to create the following partitions:

Which Transact-SQL statement should you run?
A. CREATE PARTITION FUNCTION pfOrderIDRange (int)
AS RANGE LEFT FOR VALUES (0,7500000,10000000)
B. CREATE PARTITION FUNCTION pfOrderIDRange (int)
AS RANGE RIGHT FOR VALUES (7500000,10000000)
C. CREATE PARTITION FUNCTION pfOrderIDRange (int)
AS RANGE LEFT FOR VALUES (7500000,10000000)
D. CREATE PARTITION FUNCTION pfOrderIDRange (int)
AS RANGE RIGHT FOR VALUES (0,7500000,10000000)
Answer: C
Explanation:
We need to specify two boundary values that separate the partitions. And we must use RANGE LEFT as the boundary value must belong to the partition to the left.
Incorrect Answers:
A: With RANGE RIGHT the boundary value belongs to the partition to the right. It is the equivalent of >=.
C, D: Providing three boundary values will result in four partitions.
References:
https://docs.microsoft.com/en-us/sql/t-sql/statements/create-partition-function-transact-sql?view=sql-server-2017